XmlDocument에서 줄 바꿈을 사용하여 들여 쓰기 된 XML을 얻는 가장 간단한 방법은 무엇입니까?

XmlDocument에서 줄 바꿈을 사용하여 들여 쓰기 된 XML을 얻는 가장 간단한 방법은 무엇입니까?

---

나는 처음부터 XML을 구축 할 때 XmlDocument의 OuterXml속성은 이미 잘 줄 바꿈과 들여 모든 것을 갖추고 있습니다. 그러나 LoadXml매우 "압축 된"XML (줄 바꿈이나 들여 쓰기 없음)을 호출 하면 출력이 OuterXml그대로 유지됩니다. 그래서 ...

의 인스턴스에서 아름다운 XML 출력을 얻는 가장 간단한 방법은 무엇입니까 XmlDocument?

---

다른 답변을 바탕으로 XmlTextWriter다음 도우미 방법을 조사 하고 생각해 냈습니다.

static public string Beautify(this XmlDocument doc)
{
    StringBuilder sb = new StringBuilder();
    XmlWriterSettings settings = new XmlWriterSettings
    {
        Indent = true,
        IndentChars = "  ",
        NewLineChars = "\r\n",
        NewLineHandling = NewLineHandling.Replace
    };
    using (XmlWriter writer = XmlWriter.Create(sb, settings)) {
        doc.Save(writer);
    }
    return sb.ToString();
}

내가 기대했던 것보다 약간 더 많은 코드지만, 그냥 복숭아처럼 작동합니다.

---

Erika Ehrli의 블로그 에서 채택한대로 다음 과 같이해야합니다.

XmlDocument doc = new XmlDocument();
doc.LoadXml("<item><name>wrench</name></item>");
// Save the document to a file and auto-indent the output.
using (XmlTextWriter writer = new XmlTextWriter("data.xml", null)) {
    writer.Formatting = Formatting.Indented;
    doc.Save(writer);
}

---

Linq에 액세스 할 수 있으면 더 쉽습니다.

try
{
    RequestPane.Text = System.Xml.Linq.XElement.Parse(RequestPane.Text).ToString();
}
catch (System.Xml.XmlException xex)
{
            displayException("Problem with formating text in Request Pane: ", xex);
}

---

더 짧은 확장 메서드 버전

public static string ToIndentedString( this XmlDocument doc )
{
    var stringWriter = new StringWriter(new StringBuilder());
    var xmlTextWriter = new XmlTextWriter(stringWriter) {Formatting = Formatting.Indented};
    doc.Save( xmlTextWriter );
    return stringWriter.ToString();
}

---

XmlDocument이미 XmlProcessingInstruction자식 노드가 포함 된에 대해 위의 Beautify 메서드가 호출 되면 다음 예외가 발생합니다.

XML 선언을 작성할 수 없습니다. WriteStartDocument 메서드가 이미 작성했습니다.

이것은 예외를 제거하기 위해 원래 버전의 수정 된 버전입니다.

private static string beautify(
    XmlDocument doc)
{
    var sb = new StringBuilder();
    var settings =
        new XmlWriterSettings
            {
                Indent = true,
                IndentChars = @"    ",
                NewLineChars = Environment.NewLine,
                NewLineHandling = NewLineHandling.Replace,
            };

    using (var writer = XmlWriter.Create(sb, settings))
    {
        if (doc.ChildNodes[0] is XmlProcessingInstruction)
        {
            doc.RemoveChild(doc.ChildNodes[0]);
        }

        doc.Save(writer);
        return sb.ToString();
    }
}

이제 저에게 효과적입니다 XmlProcessingInstruction. 첫 번째 노드뿐만 아니라 모든 하위 노드에서 노드를 검색해야 할까요?

---

2015 년 4 월 업데이트 :

인코딩이 잘못된 또 다른 경우가 있었기 때문에 BOM없이 UTF-8을 적용하는 방법을 찾았습니다. 이 블로그 게시물을 발견 하고이를 기반으로 함수를 만들었습니다.

private static string beautify(string xml)
{
    var doc = new XmlDocument();
    doc.LoadXml(xml);

    var settings = new XmlWriterSettings
    {
        Indent = true,
        IndentChars = "\t",
        NewLineChars = Environment.NewLine,
        NewLineHandling = NewLineHandling.Replace,
        Encoding = new UTF8Encoding(false)
    };

    using (var ms = new MemoryStream())
    using (var writer = XmlWriter.Create(ms, settings))
    {
        doc.Save(writer);
        var xmlString = Encoding.UTF8.GetString(ms.ToArray());
        return xmlString;
    }
}

---

XmlTextWriter xw = new XmlTextWriter(writer);
xw.Formatting = Formatting.Indented;

---

    public static string FormatXml(string xml)
    {
        try
        {
            var doc = XDocument.Parse(xml);
            return doc.ToString();
        }
        catch (Exception)
        {
            return xml;
        }
    }

---

간단한 방법은 다음을 사용하는 것입니다.

writer.WriteRaw(space_char);

이 샘플 코드와 마찬가지로이 코드는 XMLWriter를 사용하여 구조와 같은 트리 뷰를 만드는 데 사용한 것입니다.

private void generateXML(string filename)
        {
            using (XmlWriter writer = XmlWriter.Create(filename))
            {
                writer.WriteStartDocument();
                //new line
                writer.WriteRaw("\n");
                writer.WriteStartElement("treeitems");
                //new line
                writer.WriteRaw("\n");
                foreach (RootItem root in roots)
                {
                    //indent
                    writer.WriteRaw("\t");
                    writer.WriteStartElement("treeitem");
                    writer.WriteAttributeString("name", root.name);
                    writer.WriteAttributeString("uri", root.uri);
                    writer.WriteAttributeString("fontsize", root.fontsize);
                    writer.WriteAttributeString("icon", root.icon);
                    if (root.children.Count != 0)
                    {
                        foreach (ChildItem child in children)
                        {
                            //indent
                            writer.WriteRaw("\t");
                            writer.WriteStartElement("treeitem");
                            writer.WriteAttributeString("name", child.name);
                            writer.WriteAttributeString("uri", child.uri);
                            writer.WriteAttributeString("fontsize", child.fontsize);
                            writer.WriteAttributeString("icon", child.icon);
                            writer.WriteEndElement();
                            //new line
                            writer.WriteRaw("\n");
                        }
                    }
                    writer.WriteEndElement();
                    //new line
                    writer.WriteRaw("\n");
                }

                writer.WriteEndElement();
                writer.WriteEndDocument();

            }

        }

This way you can add tab or line breaks in the way you are normally used to, i.e. \t or \n

---

When implementing the suggestions posted here, I had trouble with the text encoding. It seems the encoding of the XmlWriterSettings is ignored, and always overridden by the encoding of the stream. When using a StringBuilder, this is always the text encoding used internally in C#, namely UTF-16.

So here's a version which supports other encodings as well.

IMPORTANT NOTE: The formatting is completely ignored if your XMLDocument object has its preserveWhitespace property enabled when loading the document. This had me stumped for a while, so make sure not to enable that.

My final code:

public static void SaveFormattedXml(XmlDocument doc, String outputPath, Encoding encoding)
{
    XmlWriterSettings settings = new XmlWriterSettings();
    settings.Indent = true;
    settings.IndentChars = "\t";
    settings.NewLineChars = "\r\n";
    settings.NewLineHandling = NewLineHandling.Replace;

    using (MemoryStream memstream = new MemoryStream())
    using (StreamWriter sr = new StreamWriter(memstream, encoding))
    using (XmlWriter writer = XmlWriter.Create(sr, settings))
    using (FileStream fileWriter = new FileStream(outputPath, FileMode.Create))
    {
        if (doc.ChildNodes.Count > 0 && doc.ChildNodes[0] is XmlProcessingInstruction)
            doc.RemoveChild(doc.ChildNodes[0]);
        // save xml to XmlWriter made on encoding-specified text writer
        doc.Save(writer);
        // Flush the streams (not sure if this is really needed for pure mem operations)
        writer.Flush();
        // Write the underlying stream of the XmlWriter to file.
        fileWriter.Write(memstream.GetBuffer(), 0, (Int32)memstream.Length);
    }
}

This will save the formatted xml to disk, with the given text encoding.

---

If you have a string of XML, rather than a doc ready for use, you can do it this way:

var xmlString = "<xml>...</xml>"; // Your original XML string that needs indenting.
xmlString = this.PrettifyXml(xmlString);

private string PrettifyXml(string xmlString)
{
    var prettyXmlString = new StringBuilder();

    var xmlDoc = new XmlDocument();
    xmlDoc.LoadXml(xmlString);

    var xmlSettings = new XmlWriterSettings()
    {
        Indent = true,
        IndentChars = " ",
        NewLineChars = "\r\n",
        NewLineHandling = NewLineHandling.Replace
    };

    using (XmlWriter writer = XmlWriter.Create(prettyXmlString, xmlSettings))
    {
        xmlDoc.Save(writer);
    }

    return prettyXmlString.ToString();
}

---

A more simplified approach based on the accepted answer:

static public string Beautify(this XmlDocument doc) {
    StringBuilder sb = new StringBuilder();
    XmlWriterSettings settings = new XmlWriterSettings
    {
        Indent = true
    };

    using (XmlWriter writer = XmlWriter.Create(sb, settings)) {
        doc.Save(writer);
    }

    return sb.ToString(); 
}

Setting the new line is not necessary. Indent characters also has the default two spaces so I preferred not to set it as well.

참고URL : https://stackoverflow.com/questions/203528/what-is-the-simplest-way-to-get-indented-xml-with-line-breaks-from-xmldocument